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Generate Parentheses #11
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| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,34 @@ | ||
| //lint:file-ignore U1000 Ignore all unused code | ||
| package generateparentheses | ||
|
|
||
| /* | ||
| 初見で解くことができず、他の人の回答を見ながら解く形になってしまいました。 | ||
| 一応自分でもバックトラッキングをちゃんと理解して自力で下記のコードを書けるようにはなりました。 | ||
|
|
||
| 時間計算量と空間計算量はカタラン数になるという認識。 | ||
| https://github.com/SuperHotDogCat/coding-interview/pull/7#discussion_r1577988152 | ||
| https://github.com/Mike0121/LeetCode/pull/1#discussion_r1577919957 | ||
| */ | ||
| func generateParenthesis_step1(n int) []string { | ||
| var parentheses []string | ||
| var stack []byte | ||
| var generate func(int, int) | ||
| generate = func(open int, closed int) { | ||
| if open == n && closed == n { | ||
| parentheses = append(parentheses, string(stack)) | ||
| return | ||
| } | ||
| if open < n { | ||
| stack = append(stack, '(') | ||
| generate(open+1, closed) | ||
| stack = stack[:len(stack)-1] | ||
| } | ||
| if open > closed { | ||
| stack = append(stack, ')') | ||
| generate(open, closed+1) | ||
| stack = stack[:len(stack)-1] | ||
| } | ||
| } | ||
| generate(0, 0) | ||
| return parentheses | ||
| } | ||
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私は、closed < open が好みですが、これでもいいでしょう。
バックトラッキングの方法はいくつか他にもあるかと思うので、見ておいてください。
抜け漏れなく分類ができていればいいのです。
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ここら辺でしょうか、ありがとうございます。
fhiyo/leetcode#52 (comment)
https://discord.com/channels/1084280443945353267/1218823830743547914/1231546400714788864
https://discord.com/channels/1084280443945353267/1252267683731345438/1252591437485441024