Remove duplicates from sorted list #20
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再帰を使った方法でも解いてみると勉強になると思います。 |
TORUS0818
reviewed
May 21, 2024
| @@ -0,0 +1,33 @@ | |||
| """ | |||
| Reference: | |||
| Ryotaro25: https://github.com/Ryotaro25/leetcode_first60/pull/3/files phase1の新しくListNodeを制作して末端の値と等しくなければ飛ばすコードを真似して書いてみた | |||
nodchip
reviewed
May 21, 2024
| while head.next and head.val == head.next.val: | ||
| head.next = head.next.next | ||
| head = head.next | ||
| return dummy_head No newline at end of file |
oda
reviewed
May 21, 2024
| @@ -0,0 +1,9 @@ | |||
| class Solution: | |||
| def deleteDuplicates(self, head: Optional[ListNode]) -> Optional[ListNode]: | |||
| dummy_head = head | |||
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dummy といっているのは大抵の場合実際は不要なのだがループの回し方の都合上形式的に必要なものの場合で実際にそれを返すならば、こちらを head にしてループを node あたりで回したらどうでしょう。
nittoco
reviewed
May 21, 2024
| while head.next and head.val == head.next.val: | ||
| # recconect listnodes in order to delete duplicates | ||
| head.next = head.next.next | ||
| head = head.next |
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odaさんのコメントと関連するかもしれませんが、headという変数が動くのは個人的には違和感ありました
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問題
https://leetcode.com/problems/remove-duplicates-from-sorted-list/description/?envType=problem-list-v2&envId=xo2bgr0r